A=C

When a triangle is a equalateral triangle it is 60 degrees. Isosceles - 30 and x2 75 degrees. Scalene averagely - 40, 50, 90. Some key words are A=judgement/discernment B=Location/Time. Square = 1080. Triangle = 180. Point = 360 (total all).

When the angle is 60 degrees this metaphor can be theorised as feeling, work, do/make as examples: a= this is a word! (peturbed/discombobulated) b=marriage (wedding dress/z chromosome) c=paper/personal (address/number and love note).



a=b b=c c=d d=e e=f a=f a+b+c=d+e+f A=B+C+D+E+F =/> a=c/?=is/isnt +=- (a=b)(water=/>ice) >=process =/> (equals is/or process) g=or/aka(known is)/(?)()=eg a=equal b=process c=make d=do e=justice f=question h=job i=potential, determinism (decide/question). outcome
a=home. b=bus station. c=bus station/work. d=route of ab. e=route of bc. f=route of ac. g=midway of d. h=midway of e. i=midway of f.

tautology

You have a triangle with each corner named a, b and c and each line named d, e and f. fitting an equalateral triangle within an equalateral triangle and naming each corner point g,h and i points out the mid way points of each line d-f and naming each line of this second triangle j, k and l. I was creating a hypothetical scenario based on initially 2-3 points with an upside down triangle. a to c the horizonatal line and then a to b to c at an angle. The points ghi are all equal to one another on lines def and therefore in each journey there is a similarity or equalisation at each point ghi. if the lines def are locations/routes then the lines are distance and speed and time, but in reality all lines and points are the same and a to b is d (x1 line) and a to b to c is de (x2lines) then the distance is longer on the second route. If the speed you walk at at route f is 2mph and the speed you are at at route de is 40mph (is not equal). The time it takes you to get there with either route are different for each. What remains equal is therefore not speed, distance or time. I arrived at justice. I also noticed that the time it takes to get from a to h through route de is the same time as it takes to get from a to i through route f and the same backwards with c to g through route de and from c to a through route f. However this means that 2 midway points are equal but not all three. What you experience and the outlook you have at point i is the same as points gh?

f----.----b----.----e equalateral = a=b=c
+ /|\ + isoceles = (a+)b=c
+ . | . + scalene = a+b+c
+/ | \+
/ + | + \
x0 a----*----c 1
\ + | + /
+\. | ./+
+ \ | / +
+ \|/ +
g----.----d----.----h

x=janitor working at bus station
d=bus station
g&b=bus stop
e=home

d+e=forest route (low speed,short distance, straight line, x1linked justice, probable just outcome?)
d+b & d+g=bus route (high speed,short distance, straight line)
g+e & b+e=walk from bus stop (low speed, short distance, straight line)
d+g+e=bus route and walk (medium speed, long distance, gradient line, x2linked justice (1 per line/location)
d+b+e=bus route and walk (medium speed, long distance, gradient line, x2linked justice (1 per line/location)


Person X (Janitor//doesnt like his boring work cleaning floors and toilets at the bus station). X finishes work and wants to return home and is deciding which is the safest and better route to take. There are 2 buses that take them to two different bus stations where X would need to catch another bus to get to a bus stop in their village, each are the same distance and same speed. There is a forest between the house at the bus station where he works and forest all inbetween the other alternate bus stations. The forest outside the bus station he works there is a straight path to the house and is shorter distance but slower speed.

Everyday at at certain time, go out for a walk, sit down, meditate, write how you felt before the walk, write what you saw on the walk, write what you thought on the walk, write how you felt on the walk, write what you thought in the meditation, write how you feel

Angles are Related! I am going to discuss the theory of the relationship between the angles to probability

Probability increases by a manner of things and this is incremented in daily life. Examples of this include:

littiler the angle the more the intensity?

examples of angles

My personal analysis of this sentence is that "death comes with the territory" means territories or places are existent in all dimensions and that in life and death, death - there is indifference. You do not just black out, there is afterlife. "See you in Disneyland" is interpretted by me to mean something of like the Matrix. I think here it pushes a narrative of Simulation Theory or that there is MORE TO LIFE.

-Ric Ramirez channelled by Skye Jones-Fenleigh

How probability emanates throughout medieval force throughout consciousness. Is through items like belongings. It is also through words and meaning (syntax, demeanor, body language, cadence - syntax here is referred to the readability of a statement when written and cadence the intonation of voice when spoken. Body language is seen through the eyes which are connected to the soul and demeanor is by definition in the Merriam Webster dictionary -

The expression of the querent is (eg.smiting) in mathematics:

If “smite” is just the name of a function, then you differentiate it the same way you would any named function.

For example, if:
[ y = \text{smite}(x) ]

. then the derivative is:
[ y' = \text{smite}'(x) ]

or equivalently:
[ \frac{d}{dx}[\text{smite}(x)] = \text{smite}'(x) ]

Without a definition of what the function actually does, you can’t simplify it further.

The hyperbolic cosine function, written (\cosh(x)), is defined as:

\cosh(x)=\frac{e^x+e^{-x}}{2}

It’s called a *hyperbolic* function because it relates to hyperbolas in a similar way that ordinary sine and cosine relate to circles.

Some useful facts:

* (\cosh(0)=1)
* It’s always positive
* Its graph looks like a smooth hanging curve (similar to a parabola but exponential)
Its derivative is:

\frac{d}{dx}\cosh(x)=\sinh(x)

And the companion function is:

\sinh(x)=\frac{e^x-e^{-x}}{2}

These functions show up in:

* differential equations
* relativity and physics
* hanging cable shapes (a *catenary*)
* signal processing

The graph of (\cosh(x)) is the exact shape a perfectly flexible hanging chain makes under gravity.